GCSE Percentage Revision Notes
GCSE Percentage Revision Notes
Foundation and Higher | percentages.co.uk
Topics labelled Foundation appear on both tiers. Topics labelled Higher are examined on the Higher tier only.
1. Percentage of an amountFoundation
Use the multiplier method: multiply the amount by the decimal equivalent of the percentage.
Worked example
Find 35% of 240.
Multiplier = 35 ÷ 100 = 0.35
240 × 0.35 = 84
2. Percentage increase and decreaseFoundation
For an increase, the multiplier is greater than 1. For a decrease, the multiplier is less than 1.
Increase
Increase £320 by 15%.
Multiplier = 1 + 0.15 = 1.15
£320 × 1.15 = £368
Decrease
Decrease £320 by 15%.
Multiplier = 1 - 0.15 = 0.85
£320 × 0.85 = £272
3. Expressing as a percentageFoundation
(part ÷ whole) × 100
Worked example
A student scores 63 out of 90. What percentage is that?
(63 ÷ 90) × 100 = 0.7 × 100 = 70%
4. Percentage changeFoundation
Percentage change = (change ÷ original) × 100
Worked example
A jacket was £85, now costs £102. What is the percentage increase?
Change = £102 - £85 = £17
Percentage change = (17 ÷ 85) × 100 = 20%
5. Reverse percentagesHigher
A reverse percentage question gives you the new value after a percentage change and asks for the original value. Divide by the multiplier.
Original = new value ÷ multiplier
Worked example
After a 20% increase, a price is £144. Find the original price.
Multiplier for a 20% increase = 1.20
Original = 144 ÷ 1.20 = £120
Common mistake
Do NOT subtract 20% from £144. That gives £144 - £28.80 = £115.20, which is wrong because you would be subtracting 20% of the new (larger) value, not 20% of the original.
6. Simple interestFoundation
Simple interest is calculated on the original amount only. The interest does not grow year on year.
Interest = P × r × t ÷ 100
where P = principal, r = rate per year (%), t = number of years
Worked example
£500 is invested at 3% simple interest for 4 years. How much interest is earned?
Interest = 500 × 3 × 4 ÷ 100 = £60
Total amount = £500 + £60 = £560
7. Compound interestHigher
Compound interest is calculated on the original amount plus all accumulated interest. The total grows faster than simple interest.
A = P(1 + r/100)n
A = final amount, P = principal, r = annual rate (%), n = number of years
Worked example
£2,000 is invested at 5% compound interest for 3 years. Find the total amount.
A = 2000 × (1 + 5/100)3 = 2000 × 1.053
1.053 = 1.157625
A = 2000 × 1.157625 = £2,315.25
8. DepreciationHigher
Depreciation is a repeated percentage decrease in value. Use the same formula as compound interest, but with a multiplier less than 1.
Worked example
A car is worth £15,000. It depreciates at 12% per year for 4 years. Find its value after 4 years.
Multiplier = 1 - 0.12 = 0.88
A = 15000 × 0.884 = 15000 × 0.59969536
A = £8,995.43 (to the nearest penny)
9. Repeated and combined percentage changesHigher
When two percentage changes happen one after the other, multiply the multipliers together to find the overall multiplier.
Worked example
A price increases by 20%, then decreases by 20%. What is the overall percentage change?
Combined multiplier = 1.20 × 0.80 = 0.96
0.96 means the final price is 96% of the original, so there is an overall 4% decrease.
This result surprises many students. The two 20% changes do not cancel out, because each percentage is applied to a different base value.
10. Percentage profit and lossFoundationHigher
Percentage profit and loss are always calculated as a fraction of the cost price, not the selling price.
% profit = (profit ÷ cost price) × 100
% loss = (loss ÷ cost price) × 100
Worked example
A trader buys an item for £40 and sells it for £52. What is the percentage profit?
Profit = £52 - £40 = £12
% profit = (12 ÷ 40) × 100 = 30%
11. Practice questions
Difficulty is indicated after each question. Attempt all questions before checking your answers.
- Find 42% of 350. [Foundation]
- A television costs £480. It is reduced by 35% in a sale. Find the sale price. [Foundation]
- A shop buys a lamp for £18 and sells it for £27. Find the percentage profit. [Foundation]
- A house is valued at £180,000. Over one year its value falls to £162,000. Find the percentage decrease. [Foundation]
- £3,500 is invested at 2.5% simple interest per year. How much interest is earned in 6 years? [Foundation]
- After a 30% increase, a price is £195. Find the original price. [Higher]
- £5,000 is invested at 4% compound interest per year. Find the total amount after 5 years. Give your answer to the nearest penny. [Higher]
- A motorbike is bought for £8,400. It depreciates by 18% per year. Find its value after 3 years, to the nearest pound. [Higher]
- A price increases by 10% and then increases by a further 10%. Find the overall percentage increase. [Higher]
- A shop has a sale. All prices are reduced by 20%, then reduced by a further 15%. What single percentage discount is this equivalent to? [Higher]